2 Re: Math help Mar 16th 2009, 10:29pm hmmm... looks similar to what im doing in maths at the moment, i shall try do it tomorrow as my books are downstairs and i dont want to wake anyone up going down
3 Re: Math help Mar 16th 2009, 10:46pm Use completing the square. [CENTER][SIZE=4][/SIZE][SIZE=4] [/SIZE][SIGPIC][/SIGPIC] [/CENTER]
4 Re: Math help Mar 16th 2009, 10:48pm Kase wrote: Use completing the square. I know but I don't know how to with variables.
5 Re: Math help Mar 16th 2009, 10:56pm It's the same process as when you substitute numbers. ax^2 + bx = -c x^2 + bx/a = -c/a x^2 + bx/a + b^2/4a^2 = b^2/4a^2 - c/a (x + b/2a)^2 - (b^2/4a^2 - c/a) = 0 [CENTER][SIZE=4][/SIZE][SIZE=4] [/SIZE][SIGPIC][/SIGPIC] [/CENTER]
7 Re: Math help Mar 16th 2009, 11:44pm It's so hard to read on the computer because of the ^2 and things. Edit:These should work ≠ < ≤ ≥ > ÷ × ² ³ ⅛ ⅜ ⅝ ⅞ ⅓ ⅔ ¼ ½ ¾ ½ The post was edited 2 times, last by Kevin (Mar 16th 2009, 11:50pm).
8 Re: Math help Mar 17th 2009, 1:21am -(b/2a), to make things simpler. Kase already described how to solve for it.. vertex = (-b/2a, f(-b,2a)) When commenting on a Joke forum. ;)Sieg Heil like an iron fascist fist, mein Fuhrer.